Esmeralda is a Brazilian telenovela produced by SBT in association with Televisa and originally broadcast from December 6, 2004, to July 19, 2005. It is a Brazilian adaptation of the Mexican telenovela Esmeralda (1997), itself based on the original story by Delia Fiallo. Adapted by Henrique Zambelli and Rogério Garcia, the telenovela stars Bianca Castanho and Cláudio Lins. The story follows Esmeralda, a young woman who has been blind since birth after being accidentally switched with another baby shortly after her birth. Raised by a humble family in the countryside, she grows up unaware of her true identity. When she falls in love with José Armando, the son of a wealthy landowner, their romance is threatened by family secrets, prejudice, social differences, and the revelation of the truth about her origins.
- Status
- Ended
- Original Language
- Portuguese
- Production
- SBT
- Network
- SBT
- Created By
- Henrique Zambelli, Delia Fiallo, Rogério Garcia
- Last Episode
- S1 E194 · Jul 19, 2005
Cast
Media
Frequently Asked Questions
Where can I watch Esmeralda online for free?
You can stream Esmeralda (2004) right here on FlixWow — every episode, in HD, completely free. No subscription, no signup, nothing to install.
What is Esmeralda about?
Esmeralda is a Brazilian telenovela produced by SBT in association with Televisa and originally broadcast from December 6, 2004, to July 19, 2005. It is a Brazilian adaptation of the Mexican telenovela Esmeralda (1997), itself based on the original story by Delia Fiallo. Adapted by Henrique Zambelli and Rogério Garcia,…
How many episodes does Esmeralda have?
Esmeralda has 194 episodes — all available to watch free on FlixWow.
Who stars in Esmeralda?
The series stars Bianca Castanho, Cláudio Lins, Lucinha Lins, Paulo César Grande, Karina Barum and more.
When was Esmeralda released?
Esmeralda was released in 2004 and is streaming free on FlixWow.
Is Esmeralda worth watching?
Esmeralda holds a rating of 7.9/10 from viewer votes (4 ratings). Watch it free on FlixWow and judge for yourself.