“If you Wander over Yonder, just you and me.”
The adventures of Wander, an eternally-optimistic intergalactic traveler and constant do-gooder, and his quick-tempered but loyal steed and best friend, Sylvia. The friendliest face in outer space, Wander journeys across the galaxies to spread good cheer and to help anyone he can — much to his overly pragmatic stallion’s chagrin. Their fun-loving escapades often lead them to clash with the evil villain Lord Hater and his army of Watchdogs, who travel from planet to planet trying to make hate the order of the day. Together, the best friends travel through the cosmos, happening upon one freewheeling adventure after another and making new friends and foes.
- Status
- Ended
- Original Language
- English
- Production
- Disney Television Animation
- Network
- Disney XD
- Created By
- Craig McCracken, Joe Pitt
- Last Episode
- S2 E40 · Jun 27, 2016
Cast
Media
Official Trailer
Frequently Asked Questions
Where can I watch Wander Over Yonder online for free?
You can stream Wander Over Yonder (2013) right here on FlixWow — every episode, in HD, completely free. No subscription, no signup, nothing to install.
What is Wander Over Yonder about?
The adventures of Wander, an eternally-optimistic intergalactic traveler and constant do-gooder, and his quick-tempered but loyal steed and best friend, Sylvia. The friendliest face in outer space, Wander journeys across the galaxies to spread good cheer and to help anyone he can — much to his overly pragmatic stallion…
How many episodes does Wander Over Yonder have?
Wander Over Yonder has 79 episodes across 2 seasons — all available to watch free on FlixWow.
Who stars in Wander Over Yonder?
The series stars Jack McBrayer, April Winchell, Keith Ferguson, Tom Kenny, Noël Wells.
When was Wander Over Yonder released?
Wander Over Yonder was released in 2013 and is streaming free on FlixWow.
Is Wander Over Yonder worth watching?
Wander Over Yonder holds a rating of 7.5/10 from viewer votes (102 ratings). Watch it free on FlixWow and judge for yourself.